I'm experimenting a bit with chaos in robocode now, with interesting results...

Starting numbers: Number 1: 1 Number 2: 2 Number 3: 3 Iteration 1: number1=0; number2=-6; number3=-18 Iteration 2: number1=0; number2=-126; number3=-1026 Iteration 3: number1=0; number2=-48006; number3=-3161106 Iteration 4: number1=0; number2=-6913872126; number3=-29977782913026 Iteration 5: number1=0; number2=-143404883344780900000; number3=-2.6960024051416305e+27 Iteration 6: number1=0; number2=-6.169488170139066e+40; number3=-2.1805286905588372e+55 Iteration 7: number1=0; number2=-1.1418775284445764e+82; number3=-1.426411611105071e+111 Iteration 8: number1=0; number2=-3.911652869900083e+164; number3=-6.103950252886094e+222 Iteration 9: number1=0; number2=-Infinity; number3=-InfinityPerhaps the numbers can represent the time in a game. Notice the difference in the three numbers after just two iterations of the chaos function! and the function isn't complicated or slow at all:

0: set the value of n 1: n(sorry about the html, it's the only way i can write it. the formula's also at [1]). Anyways, a simple formula like this can yield very different results with just a slight change. :) maybe I'll somehow put it into an oscillator...here's the results from one more test:_{1}=r*n_{1-1}*(1-n_{1-1}) n_{1}=r*n_{0}*(1-n_{0}) 2: n_{2}=r*n_{2-1}*(1-n_{2-1}) n_{2}=r*n_{1}*(1-n_{1}) x: n_{x}=r*n_{x-1}*(1-n_{x-1})

Starting numbers: Number 1: 100 Number 2: 99.9 Number 3: 99.8 Iteration 1: number1=-29700; number2=-29640.330000000005; number3=-29580.719999999998 Iteration 2: number1=-2646359100; number2=-2635736408.516701; number3=-2625145729.3151994 Iteration 3: number1=-21009649466397508000; number2=-20841319253448765000; number3=-20674170308300927000 Iteration 4: number1=-1.3242161121026912e+39; number2=-1.3030817646725226e+39; number3=-1.2822639538098948e+39 Iteration 5: number1=-5.260644934657102e+78; number2=-5.094066256266167e+78; number3=-4.932602541720552e+78 Iteration 6: number1=-8.302315538560028e+157; number2=-7.784853306968881e+157; number3=-7.299170350376416e+157 Iteration 7: number1=-Infinity; number2=-Infinity; number3=-Infinity--Starrynte