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Revision 46 . . April 8, 2008 19:55 EST by Rednaxela [Answer]
Revision 45 . . April 8, 2008 19:41 EST by Starrynte [question]
Revision 44 . . July 20, 2007 4:27 EST by Starrynte [added 'question numbers']
  

Difference (from prior major revision) (no other diffs)

Added: 72a73
** Assuming that angle is from the robocode perspective (0 degrees is north), x0 = x1 - r*sin(a) and y0 = y1 - r*sin(a). It's just simply the reverse of how you find the point from a center, angle, and radius. Hope that helps. -- Rednaxela

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